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(D) In the given graph,the $t$-axis (time) is on the vertical axis and the $s$-axis (displacement) is on the horizontal axis.For a physical motion,tim

Vedclass · Accepted Answer

The graph shown is impossible.

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(D) In the given graph,the $t$-axis (time) is on the vertical axis and the $s$-axis (displacement) is on the horizontal axis.For a physical motion,time $t$ must always increase. In this graph,as the object moves from $O$ to $A$,$B$,$C$,and $D$,the value of $t$ increases. However,at point $D$,the graph shows that for a further increase in displacement $s$,the time $t$ would have to decrease,which is physically impossible.Furthermore,for any time $t$,there cannot be two different positions $s$ (or for any position $s$,there cannot be two different times $t$ in a way that violates causality). Specifically,in this $t$-$s$ graph,the slope represents $dt/ds = 1/v$. At point $D$,the curve turns back,implying that time starts decreasing,which is impossible.Therefore,the graph shown is impossible.

List-$I$	List-$II$
$1$. Nitrogen molecules	$(A)$ Continuous spectrum
$2$. Incandescent solids	$(B)$ Absorption spectrum
$3$. Fraunhoffer lines	$(C)$ Band spectrum
$4$. Electric arc between iron rods	$(D)$ Emission spectrum

Which of the following options is correct for an object having a straight-line motion represented by the following graph?

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$1$. Nitrogen molecules $(A)$ Continuous spectrum
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